9x^2+88x-96=0

Solution for 9x^2+88x-96=0 equation:

9x^2+88x-96=0

a = 9; b = 88; c = -96;
Δ = b2-4ac
Δ = 882-4·9·(-96)
Δ = 11200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11200}=\sqrt{1600*7}=\sqrt{1600}*\sqrt{7}=40\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-40\sqrt{7}}{2*9}=\frac{-88-40\sqrt{7}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+40\sqrt{7}}{2*9}=\frac{-88+40\sqrt{7}}{18}
$